Bucks center Bogut out indefinitely with fractured ankle

Stephen Jackson (5) checks on Andrew Bogut (6) as he limps off the court in the first half against the Rockets.

Pat Sullivan/AP

MILWAUKEE (AP) -- Milwaukee Bucks center Andrew Bogut is out indefinitely after fracturing his left ankle Wednesday night in Houston.

It's another injury setback for the No. 1 overall pick in the 2005 draft.

Bogut's left foot came down awkwardly on a Houston player's foot after Bogut tried to block a shot in the first quarter. The Bucks said Thursday an MRI found Bogut fractured his ankle.

"I will get back from this," Bogut posted on his Twitter account Thursday night. "Injury was beyond my control."

The 7-foot center was playing in his 400th career NBA game. He left with three points, four rebounds and three blocked shots.

Bogut has averaged 11.3 points, a team-high 8.3 rebounds and a team-high two blocked shots in 12 games this season.

Bogut missed Milwaukee's Jan. 13 game against Dallas with concussion-like symptoms, and that followed a four-game absence to attend to a personal matter back home in Australia.

Bogut missed the end of the 2009-2010 season when he dislocated his right elbow, sprained his right wrist and broke his right hand in a hard fall to the floor. The injury bothered him for much of last season.

Bogut also missed 43 games, including the final 31, with an injured lower back in the 2008-09 season.

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