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1999 Ryder Cup

1999 Ryder Cup IBM
Total Points: Europe: 13 ½, USA: 14 ½
Last Updated: 9/26/1999 4:30 PM EDT
Sunday Singles
Europe USA Hole Status Points
Europe USA
Westwood Lehman 16 USA Won 3 & 2 0 1
Clarke Sutton 15 USA Won 4 & 2 0 1
Sandelin Mickelson 15 USA Won 4 & 3 0 1
Van De Velde Love III 13 USA Won 6 & 5 0 1
Coltart Woods 16 USA Won 3 & 2 0 1
Parnevik Duval 14 USA Won 5 & 4 0 1
Harrington O'Meara 18 Europe Won 1 Up 1 0
Jiminez Pate 17 USA 2 & 1 0 1
Olazabal Leonard 18 Match Halved ½ ½
Montgomerie Stewart 18 Europe Won 1 Up 1 0
Garcia Furyk 15 USA Won 4 & 3 0 1
Lawrie Maggert 15 Europe Won 4 & 3 1 0
        3 ½ 8 ½
Saturday Foursomes
Europe USA Hole Status Points
Europe USA
Montgomerie & Lawrie Sutton & Maggert 18 USA Won 1 Up 0 1
Clarke & Westwood Furyk & O'Meara 16 Europe Won 3 & 2 1 0
Jiminez & Harrington Woods & Pate 18 USA Won 1 Up 0 1
Parnevik & Garcia Stewart & Leonard 16 Europe Won 3 & 2 1 0
        2 2
Saturday Four-ball
Europe USA Hole Status Points
Europe USA
Westwood & Clarke Mickelson & Lehman 17 USA Won 2 & 1 0 1
Parnevik & Garcia Love III & Duval 18 Match Halved ½ ½
Jiminez & Olazabal Leonard & Sutton 18 Match Halved ½ ½
Montgomerie & Lawrie Woods & Pate 17 Europe Won 2 & 1 1 0
        2 2
Friday Foursomes
Europe USA Hole Status Points
Europe USA
Montgomerie & Lawrie Duval & Mickelson 16 Europe Won 3 & 2 1 0
Garcia & Parnevik Lehman & Woods 17 Europe Won 2 & 1 1 0
Jiminez & Harrington Love III & Stewart 18 Match Halved ½ ½
Westwood & Clarke Maggert & Sutton 16 USA Won 3 & 2 0 1
        2 ½ 1 ½
Friday Four-ball
Europe USA Hole Status Points
Europe USA
Parnevik & Garcia Mickelson & Furyk 18 Europe Won 1 Up 1 0
Montgomerie & Lawrie Love III & Leonard 18 Match Halved ½ ½
Jiminez & Olazabal Sutton & Maggert 17 Europe Won 2 & 1 1 0
Westwood & Clarke Duval & Woods 18 Europe Won 1 Up 1 0
        3 ½ ½


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